Swapping of Two Numbers Without Using Third Variable
#include<stdio.h>
#include<conio.h>
void main()
{
int a,b;
clrscr();
printf("\n Type any two numbers to swap:\n ");
printf("\n A = ");
scanf("%d",&a);
printf("\n B = ");
scanf("%d",&b);
printf("\n Numbers before swapping \n");
printf("\n A = %d \t B = %d",a,b);
a=a+b;
b=a-b;
a=a-b;
printf("\n\n Numbers after swapping\n");
printf("\n A = %d \t B = %d",a,b);
getch();
}
Output :
When we used a third variable we interchanged the values of variables and swapped the numbers. Here ,
- we have added both the numbers (A and B) and stored the total in one of the variables(A).
- Then we subtracted both the numbers from the total one by one.
- When you subtract one number (A) from the addition of two numbers (A & B) we get the second number (B).
- Then we stored the values in appropriate variables to swap the values.
Dev C++ Program to Swap Two Numbers
#include<stdio.h>
int main()
{
int a,b;
printf("\n Type any two numbers to swap:\n ");
printf("\n A = ");
scanf("%d",&a);
printf("\n B = ");
scanf("%d",&b);
printf("\n Numbers before swapping \n");
printf("\n A = %d \t B = %d",a,b);
a=a+b;
b=a-b;
a=a-b;
printf("\n\n Numbers after swapping\n");
printf("\n A = %d \t B = %d",a,b);
getch();
return 0;
}
Output :
